x^2-(x-2)(x+2)=0

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Solution for x^2-(x-2)(x+2)=0 equation:


Simplifying
x2 + -1(x + -2)(x + 2) = 0

Reorder the terms:
x2 + -1(-2 + x)(x + 2) = 0

Reorder the terms:
x2 + -1(-2 + x)(2 + x) = 0

Multiply (-2 + x) * (2 + x)
x2 + -1(-2(2 + x) + x(2 + x)) = 0
x2 + -1((2 * -2 + x * -2) + x(2 + x)) = 0
x2 + -1((-4 + -2x) + x(2 + x)) = 0
x2 + -1(-4 + -2x + (2 * x + x * x)) = 0
x2 + -1(-4 + -2x + (2x + x2)) = 0

Combine like terms: -2x + 2x = 0
x2 + -1(-4 + 0 + x2) = 0
x2 + -1(-4 + x2) = 0
x2 + (-4 * -1 + x2 * -1) = 0
x2 + (4 + -1x2) = 0

Reorder the terms:
4 + x2 + -1x2 = 0

Combine like terms: x2 + -1x2 = 0
4 + 0 = 0
4 = 0

Solving
4 = 0

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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